we weigh S1 against S2; if balanced it is S3 - else it is the heavy of S1 and S2. I later went back and refined it a little, so here it is. Me and my wife sat down to try and solve the "12 islanders riddle" from Brooklyn Nine Nine, this is our solution. Ackermann Function without Recursion or Stack. (Third Use)notethis works equally well if the group was lighter, just replace terms for appropriate identification. There are no scales or other weighing device on. :p, haha yeah loved the episode! Answer explained - step by step Number the islanders 1 to 12 First weigh 1, 2, 3, 4 vs 5, 6, 7, 8 on the seesaw. Each islander is given a position to sit on the seesaw for each round. However only three measurements are allowed. Thus we need to log224 bits of information to solve the puzzle. (Third Use), If the see saw is not balanced, remove one from each end. You already know if the different man is heavier or lighter from the second weigh, so whichever one is heavier or lighter in the second weigh is the answer. (Second Use), If the see saw balances, remove all but one from the seesaw and put one of the remaining two opposite them. (Third Use), If the two groups of 4 don't balance remember which side was lighter, have three get off one end and the remaining person swap places with one of the other four. Solution 2c. Thanks for the explanation, I think the part where you highlight the Islanders and why theyre heavier or lighter really made me understand what you were going on about. IF the scale is unequal, then you know the odd man is within the group 8-11. There are no scales or other weighing device on the island. I just saw the episode last night and I literally couldn't sleep until I figured it out. The key to this problem is making sure all three output values (left side heavier, right side heavier, two sides the same) are possible and informative in almost every comparison you do so that we can eek log224 bits out of the comparisons. Most Simple Solution to Holt's "12 men on an island with a seesaw" brainteaser! If the light side men are all of equal weight, the heavy side is then ordered to switch positions until the balance is no longer achieved, when the balance is lost, the last man to move is the heavier man. Surprisingly, they never did the grand conclusion was that no one, not even the captain who posed it in the first place, was able to figure it out. neutral islander to figure out if it is heavy or light. seesaw: R1 L2 L3 L4 L1 S2 S3 S4 (balanced) test all the cases: go test . This gives you your man. (named after their starting position, L1 = Left 1, R1 = Right 1, S1 = Side 1 etc..), We now know that the odd islander are amongst S1 S2 S3 S4 Is the set of rational points of an (almost) simple algebraic group simple? If you found that the second group weigh was unequal, then weigh 9 vs 10. The biggest problem is that you do not know whether the odd man is heavier or lighter. The island has no escapes, but there is a seesaw. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. The only thing you can use is a see-saw, which can balance one man or group of men against another man or group of men. Set it up so deduction eliminates everything else and your gold. The riddle, as you'll recall, is this: There are twelve men on an island. Put 1 on one end and 2 on the other (Third Use) if one is lighter they are the odd weight otherwise it is 3. No Scenarios, No Cases, Just The Simple Answer.Instagram: https://www.instagram.com/lifeprojxFacebook: https://www.facebook.com/lifeprojx It is of indeterminate length I wish for my see saw to be long enough to place 12 on either side, but only six will be on either side of the fulcrum. That's true, but I don't think you have to know if they are lighter or heavier, just who it is. Are you sure you want to create this branch? (Second Use), If the see saw balances, remove all but one from the seesaw and put one of the remaining two opposite them. 11 of them weigh the same and one of them is either slightly It is impossible to know both for sure in only three steps.). @emdee - Here is the link that you posted in the question. If they are equal, it is the remaining man not being measured. (seesaw measurement number 3), 2.A.3 if right is heavy Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. The answer to 12 Men On An Island Riddle is " First weigh 1, 2, 3, 4 vs 5, 6, 7, and 8 on the seesaw to see if they are equal. 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. And there's another twist: you're only allowed to use the see-saw three times. Bottom line? But you can only use the seesaw 3 times. There you have it, no islanders ever get off the see saw, and they just get on it once. If the seesaw remains neutral, Group C has the person with different weight. The second measurement was unequal, but the balance of weight shifted. (seesaw measurement number 3), 2.B.2 if balanced You can shift some of them onto the see saw with the other men and bump some off (aka. If the seesaw reverses, ether 4 or 5 is the oddly weighted one. You can use the see-saw to figure out which is the odd man, but you can only use it 3 times. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. One problem - you have to figure out which person it is too. Heres the brain teaser, verbatim from the show: There are 12 men on an island. Jordan's line about intimate parties in The Great Gatsby? What is the arrow notation in the start of some lines in Vim? Death by roo roo. You can only use it three times.. (Third Use), If the see saw is not balanced, remove one from each end. Can a VGA monitor be connected to parallel port? The results of that 4x4 measurement will indicate to you to a second specific group of 4 to measure, and from there, only 2. On one side of a balanced see-saw is an ice cube, on the other side is a basketball. Have something to tell us about this article? If A > B, then weigh A1, B1, and B2 against B3, B4, and C1. If they are equal then. if balanced it is L4 - else it is the heavier of L2 and L3. Applications of super-mathematics to non-super mathematics. 1: Start putting all twelve men on the see-saw, but have them get on in pairs (one on each end at a time) so that the see-saw stays balanced. OK, I think I have it, now the problem of explaining it, here goes: We are going to name the islanders 1 2 3 4 5 6 7 8 9 10 11 12. That person is the heavier (or lighter). Hope you all sleep well after reading this. Without loss of generality suppose that 1,2,3,4 is heavier than 5,6,7,8. You can only use it three times.. Riddle: There are 12 people on an island and one is heavier than the others. Can patents be featured/explained in a youtube video i.e. If one is heavier they are the odd one otherwise it is 6. Note that this implies that the first comparison must yield more than 1 bit of information. The island has no scales but there is a see-saw. Show Answer PREV NEXT by Mikhael Panju v1. There are 12 men on an island. Create an account to follow your favorite communities and start taking part in conversations. What is the answer to the seesaw riddle? Now we know that the different man is among {9,10,11,12}. There will be only one result, assume that whichever side falls downward is the alphabetic group. 12 men live on an island. Suppose the previous two groups were 1234 and 5678, shuffle them to create a new group of 5 and 4678 then three of the third four say abcd get on with 5 to get as an example abc5 and 4678. Start off by weighing 4 against 4, setting the other 4 aside completely. IF the scales are equal, then you know it was one of the 3 men who were removed from the scale : 6-8. sideline: L1 L2 L3 S4 L4 R4, we now know that the lighter islander are amongst S1 S2 S3. L: sit on the left, R: sit on the right, -: don't sit on the seesaw.. You must figure out which. Split the men into 3 groups of 4 and weigh 2 groups against each other [1, 2, 3, 4] VS. [5, 6, 7, 8]. I originally thought it would take 6 on one side, 6 on the other, and go from there, but then I realized the islander can weigh more OR less, so you couldn't find out that way. New post because the last one got too old. You have to figure out which Islander is the heaviest using a seesaw. Happy problem solving. After spending some time with it (and finally solving it), I get why they didnt give an answer. 2) They are different. Dealing with hard questions during a software developer interview, "settled in as a Washingtonian" in Andrew's Brain by E. L. Doctorow. must figure this out in three measurements of the seesaw or less., (You need Go installed) All weigh the same except one who is lighter (or heavier, for the purposes of the puzzle solution it's the same; you follow the same steps). seesaw: L1 L2 L3 L4 R1 R2 R3 R4 (balanced) The exciting catch? Please Use 2 - Remove six(6) men from the see-saw, three(3) from both groups. There are 12 men on an island. sideline: S1 R2 R3 R4, we know there is a heavy islander amongst L2 L3 L4 The seesaw will balance perfectly. You can figure out both in three steps. There are 12 men on an island. I could not add my own answer and I felt that editing that post was more work than necessary so forgive me for posting again, as well as for answering below as this was my solution to 'Holts' riddle. Is there a way to only permit open-source mods for my video game to stop plagiarism or at least enforce proper attribution? There are 2 possible outcomes, either they are equal, or unequal. 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. 11 of them weigh the same and one of them is either slightly heavier or slightly lighter. to use Codespaces. The only case where you dont is 1.1.1 where the seesaw balances every time and its a process of elimination, the oddly weighted person never gets on the scale so you cant know. How is "He who Remains" different from "Kang the Conqueror"? I like Rosa's answer squeeze until fatty confesses. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. It only takes a minute to sign up. Learn more. One of the islanders weighs slightly more or less then the other 11, and you must discover which, by placing islanders in groups on the seesaw. After you do your fist step you will have eliminated some of the men as possiblilities (they are neutral). New comments cannot be posted and votes cannot be cast. B, then weigh A1, B1, and they just get on once.: L1 L2 L3 L4 L1 S2 S3 S4 ( balanced ) all! Solving it ), I get why they didnt give an answer solving it ), if scale... Who it is S3 - else it is the heavy of S1 and S2 notethis works equally if... Possiblilities ( they are equal, it is 6: R1 L2 L3 L4 the reverses... Islander is given a position to sit on the seesaw for each round saw the episode last night and literally! 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